A conducting bar of mass 1.5kg, length 0.35m, makes a circuit with resistor R (R

Question

A conducting bar of mass 1.5kg, length 0.35m, makes a circuit with resistor R (R= 9.0 ohms). The bar moves to the left without friction in a horizontal plane, moving on parallel conducting rails. A constant magnetic field B (0.3 T) is directed perpendicular, in the outward direction to the plan of the page.
At what contact speed should the bar move to produce an 8.5 mA current in the resistor? Which direction is the current? As what rate is the energy delivered to the resistor? Where is the energy coming that is delvered to the resistor?

Explanation / Answer

emf=Blv=ir=.0085*9=.0765V

v=.0765/Bl=.0765/.3*.35=.728m/s

v=.728m/s

current direction isclockwise

energy to resistor=.688J

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