Two circular loops are parallel, coaxial, and almost in contact, 1.02 mm apart (

Question

Two circular loops are parallel, coaxial, and almost in contact, 1.02 mm apart (Fig. P19.58). Each loop is 9.6 cm in radius. The top loop carries a clockwise current of 140 A. The bottom loop carries a counterclockwise current of 140 A.

http://www.webassign.net/sf5/p19_60.gif

Figure P19.58
(a) Calculate the magnetic force that the bottom loop exerts on the top loop. (Hint: The distance between the loops is small in comparison to the radius of curvature, so the loops may be treated as long, straight, parallel wires.)
N

(b) The upper loop has a mass of 0.0218 kg. Calculate its acceleration, assuming that the only forces acting on it are the force in part (a) and its weight.
m/s2

Explanation / Answer

a)

F = i2L /(2d)

   = 4*3.14e-7*140*140*2*3.14*0.096/(2*3.14*1.02e-3)

   = 2.32 N

b)

a = F/m - g

= 2.317/0.0218 - 9.8

= 96.48 m/s2

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