Two children pull a third child on a tricycle by means of two ropes tied to the

Question

Two children pull a third child on a tricycle by means of two ropes tied to the handlebars. The combined inertia of the child and tricycle is 36 kg . One child pulls with a constant force of 97 Ndirected to the right of the straight-ahead direction at an angle of 45 .

Part A: If the second child pulls with a force of 80 N , at what angle to the left of the straight-ahead direction must he pull to make the tricycle move straight ahead?

Part B: With the second child pulling at the angle you calculated in part A, what is the acceleration of the tricycle?

Part C: What is the work done on the tricycle by the two ropes if the children pull constantly like this while the tricycle moves 2.0 m?

Explanation / Answer

F1x = F1*cos45

F1y = F1*sin45

F2x = F2*costheta

F2y = -F2*sintheta

the tricycle is moving along x

Fnety = 0

F1y + F2y = 0

F1*sin45 = F2*sintheta

97*sin45 = 80*sintheta

theta = 59.02 degrees

+++++++

B)

Fnet = F1x+ F2x = (97*cos45)+(80*cos59.02) = 109.77 N

acceleration = a =Fnet/m = 109.77/36 = 3.05 m/s^2

+++++

C)

W = Fnet*s = 109.77*2 = 219.54 J

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