Two children (m = 31.0 kg each) stand opposite each other on the edge of a merry

Question

Two children (m = 31.0 kg each) stand opposite each other on the edge of a merry-go-round. The merry-go-round, which has a mass of 1.64 times 10^2 kg and a radius of 1.2 m, is spinning at a constant rate of 0.48 rev/s. Treat the two children and the merry-go-round as a system. (a) Calculate the angular momentum of the system, treating each child as a particle. (Give the magnitude.) kg middot m^2/s (b) Calculate the total kinetic energy of the system. J (c) Both children walk half the distance toward the center of the merry-go-round. Calculate the final angular speed of the system.

Explanation / Answer

consider merry go round as disc

solving C part

conserving angular momentum

I1*w1=I2*w2

w2=I1*w1/I2

I2=(2*31*0.6^2)+(164*1.2^2/2)=140.4

w2=625.383/140.4=4.45 radian per second

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