A boy and a girl are balanced on a massless seesaw The boy has a mass of 75 Kg a

Question

A boy and a girl are balanced on a massless seesaw The boy has a mass of 75 Kg and the girl's mass is 50 kg If the boy sits 2 0 m from the pivot point on one side of the seesaw where must the girl sit on the other side? Two children sat on opposite ends of a uniform seesaw which pivots in the center Child A has mass 60 kg and sits 2.0 m from the center Child B has mass 40 kg How far from the center must child B sit for the seesaw to balance? A uniform board of weight 40 N supports two children weighing 500 N and 350 N respectively If the support is at the center of the board and the 500-N child is 1.5 m from the center, what is the position of the 350-N child? A 10-m uniform beam of weight 100 N is supported by two ropes at the ends if a 400-N person sits at 2.0 m from the left end of the beam, what is the tension in the left rope?

Explanation / Answer

1) Answer the questions with M=F-left*r-left=F-right*r-right g= 9,81 m/s^2 F= m*g F-boy= 75*9.81= 735.75 N F-girl= 50*9.81= 490.5 N r-boy= 2m 2*735.75=490.5*r-girl r-girl= 3m

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