A box with an initial velocity of 20 ft/sec is accelerated at 5 ft/sec^2 for 5 s

Question

A box with an initial velocity of 20 ft/sec is accelerated at 5 ft/sec^2 for 5 seconds. What is the distance traveled by the box during the five seconds? A mass of 890 grams is given an acceleration of 160 cm/sec^2 by a force. Find the force in (a) dynes, (b) in Newtons. A force of 25 Newtons acts on a mass of 80 kgm. Find the acceleration in meters/sec^2. What is the acceleration of a body if its velocity is increased from 40 meters/sec to 80 meters/sec in two seconds? Solve algebraically for the value of a in the equation:

Explanation / Answer

Part 1)

This is an exercise in cinematic

x = Vo t + ½ a t2

x = 20 5 + ½ 5 52

x = 100 + 62.5

x = 162.5 ft/s

Part 2)

This issue is on the second law of Newton

F= m a

cgs units

F = 890 160

F = 1.424 105 dynes

SI units

F= 0.890 1.60

F = 1.424 N

Part 3)

F = m a

a = F/m

a = 25 / 80

a = 0.31 m/s2

Part 4)

This exercise is cinematics

Vf = Vo + a t

a = (Vf – Vo) / t

a = (80 – 40 ) / 2

a = 20 m/s2

Part 5)

we will do it step by step

x – Vo t = ½ a t2

a = (x -Vo t) 2/t2

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