A 1.41 meter bar moves through a uniform 1.2 T magnetic field with speed 2.5 m/s

Question

A 1.41 meter bar moves through a uniform 1.2 T magnetic field with speed 2.5 m/s. In each case, find emf induced between the ends of the this bar and identify which, if any end (a or b) is at higher potential. The bar moves in the direction of
a) +x axis
b) -y axis
c) +z axis
d) How should this bar move so that the emf across its ends has the greatest possible value with b at a higher potential than a, and what is this maximum emf?

Field is into the page and bar makes a 37 degree angle with the x axis

Any help is greatly appreciated

Explanation / Answer

a)
= BLV sin37 = 1.2 * 1.41 * 2.5 * sin37 = 2.55 V

The bar has free electrons. These electrons experience a magnetic force when the bar is moving at the magnetic field.

the end at the +y is at higher potential

b)

= BLV = 1.2 * 1.41 * 2.5 * cos37 = 3.38 V

the end at the +x is at higher potential

c)

= 0

d)

= BLV = 1.2 * 1.41 * 2.5 = 4.23 V

When the bar makes a -53 degree angle with the +x axis

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