A 1.3-kg cart is moving to the right with an initial speed of v0=1 m/s. It hits

Question

A 1.3-kg cart is moving to the right with an initial speed of v0=1 m/s. It hits a cart of mass 7.8 kg which is at rest. After the collision, the more massive cart is observed to move at a speed of vb=0.3 m/s to the right. (a) According to the vector model of momentum, what is the x-momentum (px) of the lighter cart after the collision? (Let right be positive and left be negative.) (b)What is the x-velocity of the lighter cart after the collision? (c)If the two carts are in contact for 0.15 s, what is the magnitude of the force felt by the 1.3-kg cart during the collision.

Explanation / Answer

m1v0 = m1v1" + m2v2"

1.3*1 = 1.3*v + 7.8*0.3

1.3 v = -1.04

v= -0.8 m/s

so lighter cart will move left with v = -0.8 m/s

a)momentum after collision of lighter cart = mV" = - 1.04 J

b) vel of light cart = -0.8 m/s

c)impulse = F*t = change in momentum

F*0.15 = 1.3( -0.8 - 1)

F = 15.6 N

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