A conducting bar of length 35 cm is being pushed to the right on two frictionles

Question

A conducting bar of length 35 cm is being pushed to the right on two frictionless rails (see figure below). The circuit is completed via a wire with a 9 Ohm resistor. (Assume that the resistance of the bar and rails is zero.) A uniform magnetic field of 0.30 T points into the page, (a) At what constant speed should the bar be moved to produce an 8.5 mA current in the resistor? (b) What is the direction of the induced current? (c) What is the direction of the magnetic force on the bar while it is being moved to the right?

Explanation / Answer

a ) current, I = V/R = Blv/R so, v = IR/Bl = 8.5*10^-3*9/(.3*.35) = 0.7286 m/s net force = 0 so, magnetic force must be opposite and equal to the external force Fapp which acts towards right ..

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.