<p>A golf ball is hit off a tee at the edge of a cliff. Its <em>x</em> and <em>y
ID: 2059416 • Letter: #
Question
<p>A golf ball is hit off a tee at the edge of a cliff. Its <em>x</em> and <em>y</em> coordinates as functions of time are given by <span class="watexinlineblock"><span class="watex watexlineheightnormal"><div class="watexline"><span>x</span> = <span>16.6</span><span>t</span></div>
</span></span> and <span class="watexinlineblock"><span class="watex watexlineheightnormal">
<div class="watexline"><span>y</span> = <span>4.08</span><span>t</span> − <span>4.81</span><span>t</span><sup>2</sup>,</div>
</span></span> where <em>x</em> and <em>y</em> are in meters and <em>t</em> is in seconds.</p>
<p>By taking derivatives, do the following. (Give the answers in terms of <em>t</em>.)
<div class="indent">(b) obtain the expression for the velocity vector <img title="varrowbold" src="http://www.webassign.net/images/varrowbold.gif" alt="varrowbold" /> as a function of time</div>
</p>
Explanation / Answer
position vector is P = 16.6ti + (4.08t - 4.81t^2)j so, velocity vector =P' =dP/dt= 16.6i + (4.08 - 9.62t)j
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