*Two people push on a 4Kg object. One force is 60N, North. The second force is 4

Question

*Two people push on a 4Kg object. One force is 60N, North. The second force is 40N, East. Find the object’s acceleration (magnitude and direction). Ignore friction. (18.03 m/s2, 56.310)

Two people trying to move a 20Kg box along the ground pull on separate ropes that are attached to the box at the same place. One rope has a force of 60N in it held 350 above the ground. The second rope has a 40N force in it and is parallel to the ground. Ignoring friction, what is the acceleration of the box? (4.46 m/s/s, in dxn of motion)

Explanation / Answer

1. The resultant force is the square root of 60N squared plus 40N squared. When you get that force, the acceleration is the force divided by the 4 kg mass. 2. Same idea as 1, solve a right triangle to get the resultant force and divide by the mass of the box to get the acceleration.

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