A circuit consists of a 12 V battery connected to a switch, which is connected t

Question

A circuit consists of a 12 V battery connected to a switch, which is connected to a light bulb of resistance 120 O and then back to the battery. If the switch is open, which statement is true of I (the current through the switch and Vs (the difference in potential across the poles of the switch)?
I = 10 A, Vs is not zero but less than 12 V
I = 0 A, Vs is not zero but less than 12 V    
I = 10 A, Vs = 0 V
I = 10 A, Vs is more than 12 V
I = 0 A, Vs = 12 V
I = 0 A, Vs = 0 V
I = 0 A, Vs is more than 12 V
I = 0.1 A, Vs = 12 V
I = 0.1 A, Vs is more than 12 V
I = 10 A, Vs = 12 V
I = 0.1 A, Vs is not zero but less than 12 V
I = 0.1 A, Vs = 0 V

seven identical wires of measurable resistance are attached consecutively to a battery of potential difference V: one end of the first wire is connected to the positive terminal of the battery; the other end of the first wire is connected to one end of the second wire; the other end of the second wire is connected to one end of the third wire, and so on. The free end of the seventh wire is connected to the negative terminal of the battery. The potential difference across wire 1 is V1, and the current flowing through wire 1 is I1, If an eighth identical wire is introduced between the seventh wire and the battery, what happens to V1 and I1?
V1 increases, I1 increases
V1 remains the same, I1 increases     
Both V1 and I1 increase
Both V1 and I1 remain the same
V1 increases, I1 remains the same
V1 remains the same, I1 decreases
Both V1 and I1 decrease
V1 decreases, I1 remains the same
V1 decreases, I1 increases

Now, seven identical wires of measurable resistance are connected across the the terminals of the battery of potential difference V. (In other words: one end of each wire is connected to the positive terminal of the battery, and the other end is connected to the negative terminal of the battery.) The potential difference across wire 1 is V1, and the current flowing through wire 1 is I1, If an eighth identical wire is now added so it connected like the others (across the battery), what happens to V1 and I1?
V1 decreases, I1 remains the same
Both V1 and I1 remain the same    
V1 increases, I1 increases
V1 remains the same, I1 decreases
V1 decreases, I1 increases
Both V1 and I1 decrease
V1 remains the same, I1 increases
Both V1 and I1 increase
V1 increases, I1 remains the same

Explanation / Answer

I = 0 A, Vs = 12 V
Both V1 and I1 decrease
Both V1 and I1 remain the same.because when  additi0nal resistor is connected in parallel the new effective resistance of circuit  is less than the older one.so current increases.that increase current will go through additi0nal resistor.

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