A block is at rest on the incline shown in the figure. The coefficients of stati

Question

A block is at rest on the incline shown in the
figure. The coefficients of static and kinetic
friction are µs = 0.47 and µk = 0.4, respec-
tively.The acceleration of gravity is 9.8 m/s2 .What is the frictional force acting on the
47 kg mass?
Answer in units of N

Part 2

What is the largest angle which the incline
can have so that the mass does not slide down
the incline?
Answer in units of degree

Part 3

What is the acceleration of the block down
the incline if the angle of the incline is 31 ?
Answer in units of m/s2

Explanation / Answer

part 1

i cant see the figure
i assume the inclination angle to be degree

frictional force = Normal reaction * static friction coeff.

= 47*9.8*(cos )* 0.47

= 216.48xcos newton -----------------(1)

part 2

let the largest inclination angle be

for block to be rest

frictional force = component of weight in direction of inclination

m*g*static friction coeff = km*g*sin

from 1&2

tan=0.851

=40.39

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