(a) Calculate the equivalent resistance of the R 1 and 5.00- resistors connected

Question

(a) Calculate the equivalent resistance of the R1 and 5.00- resistors connected in parallel.
  

(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00-, and 4.00- resistors.
  

(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00- resistor.
  

(d) Combine the equivalent resistance found in part (c) with the R2 resistor.
  

(e) Calculate the total current in the circuit.
  A

I need help with the last 3:

(f) What is the voltage drop across the R2 resistor?
V

(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00- resistor.
V

(h) Calculate the current in the 3.00- resistor.
A

Explanation / Answer

a) Parallel combination: 1/Req=1/R1 + 1/5 -> Req= 3.214 ohms b) Series combination: Req2=Req+ 4 = 7.214 c) Parallel combination: 1/Req3 = Req2 // 3 = 1/Req2 + 1/3 -> Req3= 2.119 d) Series combination: Req4=Req3 + R2 = 3.119 e) Total current: V=IR, I=V/R, I=6/3.119=1.924A f) Voltage division: Vr2=Vtotal(R2/R2+Req3)=Vtotal*R2/Req4=1.924V g) Summed voltages: Vreq3=Vtotal-1.924=4.076 (or can do voltage division again replacing R2 with Req3) h) Current: V3=Vreq3(3/3+Req2)=1.197, V=IR, I3=V/R=1.197/3=0.399A (or current division; Ireq2=Itotal(R2/Req3+R2), I3=Ireq2(Req2/(Req2+3))=0.436A) Answers are a tad bit off because I didn't keep that many sig figs (mismatch in h), but you should get the picture.

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