(a) By what factor does her time in the air increase? (b) By what factor does he

Question

(a) By what factor does her time in the air increase? (b) By what factor does her maximum height increase? (c) Verify your answer to part (a) with explicit calculations. (c) Verify your answer to part (a) with explicit calculations.    ( )s initially, ( )s after initial speed quadruples (a) By what factor does her time in the air increase? (b) By what factor does her maximum height increase? (c) Verify your answer to part (a) with explicit calculations. (c) Verify your answer to part (a) with explicit calculations.    ( )s initially, ( )s after initial speed quadruples

Explanation / Answer

from the given data, velocity of youngster increases from 1.9m/s to 7.6m/s the change of velocity 7.9m/s-1.9m/s= 6m/s (a) if 'U' is the intial velocity of her,the time taken to bounces stright up and down on a trampoline is equal to the totaltime of flight of her. the total time of flight (T) is given by, T=2U/g U1=1.9m/s and U2=7.6m/s (given) then we may take as, T1 =2 U1/g T2 =2 U2/g the change of or increasing of her time in the air T2-T1=2 U2/g - 2 U1/g =2/g(U1-U2) =2/g(7.6-1.9) =2/g(6) (where 2/g constant) the time of her in the air increases by a factor " 6" (b) the maximam height of a youngster H max = U^2/2g (from standerd formula) we have U1=1.9 m/s and U2=7.6m/s the corresponding heights H1 and H2, H2 -H1 = U2^2/2g - U1^2/2g =1/2g(U2^2-U1^2) = 1/2g(54.15) ( where 2g constant) thus , the maximam height of her incresed by a factor "54.15"

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.