A uniformly charged rod of length L with total charge -Q runs along the x-axis (

Question

A uniformly charged rod of length L with total charge -Q runs along the x-axis (from point A to point B), its end (B) is a distance L away from point O. A uniformly charged semi-circular rod (radius L) with a total charge of +Q is connected to the rod at point B. The connection of two is made at the midpoint of the semi circle and the semi circle has its opening away from the rod (like the letter "C"); point O is at the center of the semi circle. And a charged sphere of charge –Q has its center a distance 2L from O (on the right side of O). What is the electric potential at point O?

Explanation / Answer

Let q1 = -10.0 nC , and q2 = 20.0 nC E1(P) + E2(P) = 0 |E1| = |E2| |q1|/r1^2 = q2/r2^2 r2/r1 = sqr(q2/|q1|) = sqr 2 r2 = r1 + d Solving : r1 = d/(sqr2 -1) = 33.8 cm ; r2 = 47.8 cm (a) V = (1/4pi €o)(q2/r2 + q1/r1) = 110 V (b) V=0 |q1|/r1 = q2/r2 r2 = 2 r1 ; r2 + r1 = d solving r2 = 28/3 cm ; r1 = 14/3 cm E = E1 + E2 = (1/4pi€o)(|q1|/r1^2 + q2/r2^2) E is // at X axis and direct from q2 to q1.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.