You are interested in whether two loci in a population are in linkage disequilib

Question

You are interested in whether two loci in a population are in linkage disequilibrium, so you have determined the haploid genotypes for 300 randomly sampled gametes. You obtained the following counts: 4. 50 gametes with AB 50 gametes with ab 100 gametes with Ab 100 gametes with aB Is there evidence of linkage disequilibrium in this population (yes or no)? Show calculations to support your answer. Then describe what this pattern means in words without the use of mathematical expressions a. b. You have determined that selection in this population consistently favors individuals with the recessive "aa" phenotype. What (if any) change in frequency of the B allele would you expect to see as a result of this selection, assuming that there is no direct selection on phenotypic variation determined by the B locus?

Explanation / Answer

a.

YES, linkage disequilibrium is observed in the population because we are observing recombinent genotypes.

The formation of Recombinant genotypes occurs when genes are linked and they do recombination.

Linkage = recombinant / total

Here

linkage = 100/300= 33.33

So 33.33 % have Recombinant genotype

So we can say that linkage is changed by the process of linkage disequilibrium.

Here the high number of genotype is parental or original genotype and less number of gamete genotype indicate the Recombinant gamets.

when we don't go with mathematical expression then we generally can say that by observing gamut genotype we can say that recombination is occured.

recombination occurred in the situation only where genes are linked. hear a and B genes are linked that is why recombination occurred.

b.

when we observe that recessive homozygous phenotype is favoured than the frequency of allele B can be changed.

Because of linkage disequilibrium.

aaa occurs in linked form with B or b.

So we can see the change in the frequancy of B and b due to linkage disequilibrium.

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