You are asked to consult for the city\'s research hospital, where a group of doc

Question

You are asked to consult for the city's research hospital, where a group of doctors is investigating the bombardment of cancer tumors with high-energy ions. The ions are fired directly toward the center of the tumor at speeds of 5.5 imes 10^{6};{ m m}/{ m s}. To cover the entire tumor area, the ions are deflected sideways by passing them between two charged metal plates that accelerate the ions perpendicular to the direction of their initial motion. The acceleration region is 5.0 m cm long, and the ends of the acceleration plates are 1.5 m m from the patient.

What acceleration is required to move an ion 2.0 m cm to one side?

Explanation / Answer

the time the particle undergoes the acceleration is X=vt, t=X/V t=.05/(5.5*10^6)=9.09*10^-9 seconds which is the time the particle undergoes acceleration Now, because the acceleration is perpendicular to the original velocity, the speed in the y-axis will remain unchanged, so the time the particle will take to get to the body is 1.5/(5.5*10^6)=2.7*10^-7 seconds Now, we find the necessary velocity of the particle in the x-direction. .02=Vt .02=v*2.7*10^-7 v=m/s=7.407*10^4m/s Now for the last part, V=at 7.4*10^4=a*9.09*10^-9 a=8.14*10^12m/s^2 I hope this helps!

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