Steps by steps solution with clear explanation on how to get the answer please.

Question

Steps by steps solution with clear explanation on how to get the answer please.

Thanks in advance! =)

Water is discharged from a nozzle and strikes a moving trolley as shown in 4. The velocity of water is 1 m/s at point A where the diameter is 4 cm. nozzle outlet diameter is 1 cm. The trolley is moving with a velocity of 2 m/s. You may assume that the fiow in the nozzle and along the curved surface of the trolley is frictionless. You may neglect the weight of the water that is in contact with the curved surface of the trollcy, and changes in heighu elevation. (i) Determine the gauge pressure at point A and the horizontal and vertical forces exerted by the waterjet on the trolley. If the original weight of the trolley is 100 N what is the impact of the water jet (ii) on its weight? Explain your reasons with appropriate equations. You are not required to numerically determine the change in the apparent weight of the trolley. Water jet trolley Water jet Nozzle

Explanation / Answer

taking point A and the nozzle, using bernoullie equation b/w them

Patm +PA + 0.5VA2 = Patm + 0.5V12

balancing the volume flow rate b/w both the point

(area)AVA = (area)1V1 => V1 = 16 m/s

now, using first equation

PA = 127500 Pa (gauge pressure)

Horinzatal force =rate of change in the momentum of water in horizontal direction

= A1(V1 - 2) = 1.1 N (forward direction)

vertical force =rate of change in the momentum of water in vertical direction

= A1V1=1.256 N (downward direction)

(b) weight will increase due to the vertical force.

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