(c5p72) Imagine a landing craft approaching the surface of Callisto, one of Jupi
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Question
(c5p72) Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thrust) of 3552 N, the craft descends at constant speed; if the engine provides only 2398 N, the craft accelerates downward at 0.39 m/s2. What is the weight of the landing craft in the vicinity of Callisto's surface?Tries 0/10
What is the mass of the craft?
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(c) What is the free-fall acceleration near the surface of Callisto?
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Explanation / Answer
similar question just change the values of uppward force and etc upward force (thrust) of 3480 N, the craft descends at constant speed; if the engine provides only 2280 N, the craft accelerates downward at 0.41 m/s2. (a) What is the weight of the landing craft in the vicinity of Callisto's surface? (b) What is the mass of the craft? (c) What is the magnitude of the free-fall acceleration near the surface of Callisto? a) Remember, weight is the the net force which prevents an objects from falling freely. So, since at 3480 N the object descends at a constant speed (no acceleration), the weight must be: 3480 N. b) At an upward force of 2280 N, the craft decelerates because its weight(force of g on object *mass) is greater than the upward force of the engine. The difference between these two forces is the net force on the object. (3480N-2280N = 1200). At a force of 1200N, the object's acceleration is .41 m/s^2. F=ma. 1200N= m (.41m/s^2) 1200N/ (.41m/s^2) = m m= 2926.83 Kg. c) We know that at 1200 N the acceleration is .41m/s^2. However, this portion is asking for the acceleration when the engine is turned off (no upward force= free fall). In other words, the acceleration with a downward force of 3480 N. a= .41 (3480/1200)= 1.189m/s^2
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