(c)A student stands at the edge of a cliff and throws a stone horizontally over

Question

(c)A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of

(a) What are the coordinates of the initial position of the stone?

x0=0.0m (correct)

y0=40.0m (correct)

(b) What are the components of the initial velocity?
v0x=15.5 m/s

v0y= ??? m/s

(c) Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do no include units in your answer.)

vx= ???

vy=???

(d) Write the equations for the position of the stone with time, using the coordinates in the figure. (Use the following as necessary: t. Let te variable t be measured in seconds. Do not state units in your answer.)

(e) How long after being released does the stone strike the beach below the cliff?

2.857 s (correct)

(f) With what speed and angle of impact does the stone land?

vf=32.004 m/s (correct)

theta = 61.03 degrees below the horizontal (correct)

Any help would be really appreciated!

Explanation / Answer

A) Xo = 0.0 m

yo = 40.0 m

B) Vox = 15.5 m/s

Voy = 0 .0 m/s

C) Vx = Vox

Vy = gt

D) x = vox*t

y = 0.5*g*t^2

e) T = sqrt(2*h/g) = sqrt(2*40/9.8) = 2.857 s

f) speed of impact is v = sqrt(Vox^ +(g^2*t^2)) = sqrt(15.5^2 + (9.8^2*2.857^2)) = 32.02 m/s

angle theta = atan(vy/vx) = atan(gt/vox) = atan(9.81*2.857/15.5) = 61.05 degrees

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.