A total of 7.29·106 electrons are placed on an initially uncharged wire of lengt

Question

A total of 7.29·106 electrons are placed on an initially uncharged wire of length 2.05 m.

a) What is the magnitude of the electric field a perpendicular distance of 0.414 m away from the midpoint of the wire?

b) What is the magnitude of the acceleration of a proton placed at that point in space?

c) In which direction does the electric field force point in this case?

-Pointing towards the top end of the wire.
-Pointing towards the bottom end of the wire.
-Anti-parallel to the wire.
-Parallel to the wire.
-Perpendicular to the wire, pointing towards the middle of the wire.
-Perpendicular to the wire, pointing outward and away from the middle of the wire.

Explanation / Answer

wire length = WL
charge = (number of electrons * elementary charge)
lambda = (charge/WL)
E = 2k( Lambda / perpendicular distance )*((WL/2) / sqrt((WL/2)^2 +(perpendicular distance)^2))

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