an object of mass m =5.0 kg hangs from a cord around the light pulley. the lengh

Question

an object of mass m =5.0 kg hangs from a cord around the light pulley. the lenght of the cord between point P and the pulley is L = 2.0 m. how many loop will result if mass changed to 180

Explanation / Answer

dots represent Nodes formed on cord (support points must be nodes O O O O O O O ..1 2. 3 .4. 5 6 loops < .. >< .. > so length L = separation of 7 nodes (6 loops) L = ? + ?+ ? = 3? or L(n) = N (?/2) >>>>>>>>>>>>>>>> >>> N =6 >> L = 3? = 2 ? = 2/3 frequency (n) = v / ? = (1/?)v(T/mo) where T = tension = 6*g = 6*9.8 = 58.8 N mo= lineat mass density = mass/length n = (3/2)v(58.8/mo) = 180 a) mo = 4.083*10^-3 kg/m ------------ b) n = (1/?)v(T/mo) = (N/2L)v(mg/mo) when m is changed from 6 kg to 216 kg (m1) >>> and n, L mo are fixed N = k /v(m) where k is constant N1 = k /v(m1) N1 = N * v(m/m1) = 6*v(6/216) = v(6*36/216) = 1 only 1 loop will be formed --------------- c) N2 = N * v(m/m2) = 6 v(6/8.64) = 5 loops

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.