<p><span>Three charged particles form a triangle: particle 1 with charge </
ID: 2044422 • Letter: #
Question
<p><span>Three charged particles form a triangle: particle 1 with charge </span><em>Q</em><sub>1</sub><span> = </span><span>72.0</span><span> nC is at </span><em>xy</em><span> coordinates (0,3.00 mm), particle 2 with charge </span><em>Q</em><sub>2</sub><span> is at </span><em>xy</em><span> coordinates (0,-3.00 mm), particle 3 with charge </span><em>Q</em><sub>3</sub><span> = </span><span>24.0</span><span> nC is at </span><em>xy</em><span> coordinates (4.00, 0 mm). In unit-vector notation, what is the electrostatic force on particle 3 due to the other two particles if </span><em>Q</em><sub>2</sub><span> has the following charges?</span></p><p>
<div class="indent">(a) <em>Q</em><sub>2</sub> = <span>72.0</span> nC<br />(b) <em>Q</em><sub>2</sub> = <span>-</span><span>72.0</span> nC</div>
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Explanation / Answer
similar problem 1. The problem statement, all variables and given/known data Three charged particles form a triangle: particle 1 with charge Q1=80nC is at xy coordinates (0,3.00mm) particle 2 with charge q2 is at (0,-3.00mm) and particle 3 is at(4.00mm,0). In unit vector notation, what is the electrostatic force on particle 3 due to the other two particles if Q2 is equal to (a) 80.0 nC and (b) -80nC? The book lists the answers as: (a).(0.829N)i and (b) (-.621N). 2. Relevant equations F= (|Q1||Q2|*K)/r^2 k=permittivity constant 8.99x10^9 r= distance between the charges theta= arctan(y/x) 3. The attempt at a solution I have tried countless different ways to do it and can't seem to get the book's answer. I have played around with the numbers for over 3 hours and havent found anything that works. Any help would be GREATLY appreciated as I have no idea how close or far away I am. The last way I tried it was by drawing out the triangle. I found theta to be arctan(3/4)=36.869degrees F=((.64x10^24)*8.99x10^9)/(6x10^-3)^2=159.822 nC/m^2 Fx=159.822cos(36.869)=-127.851 Fy=159.822sin(36.869)=95.89132 Fy= 159.822 sqrt((159.822+95.89132)^2+(-127.851)^2))=285.8973
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