<p><br></p><p>Two steel juggling balls each carry a charge of 2.75 ?C. There is

Question

<p><br></p><p>Two steel juggling balls each carry a charge of 2.75 ?C. There is a repulsive force between them of 1.35 N. What is the distance between the centers of the two balls?<br><br> I knew we have to use coulombs law which is... <br><img src="https://media.cheggcdn.com/media%2F903%2F9033caec-517e-46fd-92db-ffb88c0f1aa5%2FphpM9TdCk.png" data-mce-src="https://media.cheggcdn.com/media%2F903%2F9033caec-517e-46fd-92db-ffb88c0f1aa5%2FphpM9TdCk.png">&nbsp;<br><br>i got 0.0203 as the answer which is wrong...please help!</p>

Explanation / Answer

Use coulomb's law. F = K q1 q2 / d^2, where K is a constant (9x10^9 Nm^2/C^2), q1 and q2 are charges in coulombs, and d is the distance between them. 1.35N = (9x10^9)(2.75x10^-6)(2.75x10^-6) /d^2, d = .22m

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