You have 2.6 kg of water. One mole of water has a mass of 18 g/mole and each mol

Question

You have 2.6 kg of water. One mole of water
has a mass of 18 g/mole and each molecule
of water contains 10 electrons since water is
H2 O.
What is the total electron charge contained
in this volume of water? The elementary
charge is 1.6 × 10-19 C.
Answer in units of C

Explanation / Answer

As you have (2.6Kg), you have 2600/18 => 144.44 moles of water. And as one mole is 6.022x10^23, you have a total of 144.44 x 6.022x(10^23) => 8.69 x (10^25) molecules of H2O. Which in turn equals: 8.69 x (10^26) electrons (as there are 10 electrons per molecule). So that's 8.69 x (10^26) electron volts of energy, and as 1 eV = 1.6x(10^-19) coulombs, the total electron charge, in C, must equal: 8.69 x (10^26) x 1.6 x (10^ -19) => 13.91 x 10^7 C

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.