Determined the magnitude of the force between two point charges, Q1=-2e located
ID: 2043644 • Letter: D
Question
Determined the magnitude of the force between two point charges, Q1=-2e located at (-3.60cm,+4.10cm) and Q2=-8e located at 9-0.60cm,-8.60cm). it now wants me to calculate the direction of the force that Q1 exerts on Q2 and give the answer in the form of abc.d degrees clockwise from the +x axis direction and round to the nearest tenth of a degree.
the answer to this problem is 2.17 x 10^-25 N
But there is a second part of the problem I need help with
it says: calculate the direction of the force that Q1 exerts on Q2. Give the answer in the form of abc.d degrees, clockwise from the positive (+) x-axis direction and round to the nearest tenth of a degree.
Please help me solve to be able to work future problems thanx
Explanation / Answer
distance r= (-0.36+0.6)^2 + ( 4.1+8.6)^2 = 0.0576+161.29 = 161.3476cm^2 = 0.0161 m^2 E= 9 x10^9 x 2 x2 x 10^-38 / 0.0161 =2.236 x10^-26 N/c =2.236 e-26 N/c
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