This first part already have been answered: Two negative, equally charged drops

Question

This first part already have been answered:

Two negative, equally charged drops of water, 0.80 mm apart, exert an electrostatic force of 78.5 x 10-9 N on each other. Determine the net charge on each drop. Give your answer in the form "a.bc x 10^(y) unit".

For the previous problem determine the number of electrons that must be removed from each drop to cause the net charge on each drop. Give your answer in the form "a.bc x 10^(y) electrons".

Please help me solve the highlighted part of the question please

Explanation / Answer

F=9 x 10^9 x q1 x q2 / (r^2) = 78.5 x 10^-9 q1=q2=2.36 x 10^-12 c 1 electron = 1.6 x 10^-19 c n x 1.6x10^-19 = 2.36 x 10^-12 n = 1.476 x 10^ 7 electrons

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