This expert answer contains algebra that goes beyond the prerequisite understand

Question

This expert answer contains algebra that goes beyond the prerequisite understanding for Physics 12. I am hoping someone could please give me a more detailed solution of the steps required to solve without using this type of vector notation - as we have not studied it yet at this level and I do not understand. Or at least give an explanation for this unit vector notation.

Thanks so much

(II) At each corner of a square of side there are point charges of magnitude Q, 2Q, 3Q, and 4Q (Fig. 16-54). Determine the magnitude and direction of the force on the charge 2Q 20 40 30

Explanation / Answer

i denotes the direction of x axis and j denotes the direction of y-axis

Force on 2Q due Q is directed along x axis so (i) comes with it in in the first term

Force on 2Q due 3Q is directed along x axis so (j) comes with it in in the second term

Force on 2Q due 4Q is directed along the diagonal of the square. so we break this force into two parts one along x axis and other along y-axis

so those cos(45) and sin(45) terms come there.

also i isused after cos(45) to denote the direction of x-axis and j with sin(45) to denote the direction of y-axis

To find the magnitude of a vector, we square and add the x & y components and finally take square root of the sum.

By doing that we get the magnitude if the force.

the angle made by a vector is inverse tan(y-component/x-component).

If still anything isn't clear do comment

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