0 Degl /26/2018 12:00:00 AM-Due Date: 4/13/2018 11:59:00 Dale PM End Date: 5/31/
ID: 2041288 • Letter: 0
Question
0 Degl /26/2018 12:00:00 AM-Due Date: 4/13/2018 11:59:00 Dale PM End Date: 5/31/20181 (17%) Problem 4: A ball with an initial velocity of 9.6 m/s rolls up a hill without slipping. Randomized Variables v9.6 m/s X 50% Part (a) Treating the ball as a spherical shell, calculate the vertical height it reaches, in meters. hi = 7.841 sinO | cos() | tanO | ?| (I") | 7| 8| 9|HOME cotan0 asin0 acos0 atan0 acotan0sinh0 coshO tanh0 cotanho 4 5 6 1 2 3 END O Degrees O Radians 01 BACKSPACE EL CLEAR Submit Hint I give up! Feedback: 5% deduction per feedback. Hints: 4%deduction per hint. Hints remaining: 2 50% Part (b) Repeat the calculation for the same ball if it slides up the hill without rolling.Explanation / Answer
a)
By Conservation of energy
mgh =(1/2)mV2 +(1/2)IW2
MOment of inertia of spherical shell
I=(2/3)mr2
since V=rW
=>mgh =(1/2)mV2 + (1/2)(2/5)mr2(V/r)2
gh =(1/2)V2 +(1/5)mV2
=>h=(7/10)(V2/2g)
h=(7/10)(9.62/9.81)
h=6.576 m
b)
By Conservation of energy
(1/2)mV2 =mgh
(1/2)*9.62 =9.81*h
h=4.7 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.