Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

0 Degl /26/2018 12:00:00 AM-Due Date: 4/13/2018 11:59:00 Dale PM End Date: 5/31/

ID: 2041288 • Letter: 0

Question

0 Degl /26/2018 12:00:00 AM-Due Date: 4/13/2018 11:59:00 Dale PM End Date: 5/31/20181 (17%) Problem 4: A ball with an initial velocity of 9.6 m/s rolls up a hill without slipping. Randomized Variables v9.6 m/s X 50% Part (a) Treating the ball as a spherical shell, calculate the vertical height it reaches, in meters. hi = 7.841 sinO | cos() | tanO | ?| (I") | 7| 8| 9|HOME cotan0 asin0 acos0 atan0 acotan0sinh0 coshO tanh0 cotanho 4 5 6 1 2 3 END O Degrees O Radians 01 BACKSPACE EL CLEAR Submit Hint I give up! Feedback: 5% deduction per feedback. Hints: 4%deduction per hint. Hints remaining: 2 50% Part (b) Repeat the calculation for the same ball if it slides up the hill without rolling.

Explanation / Answer

a)

By Conservation of energy

mgh =(1/2)mV2 +(1/2)IW2

MOment of inertia of spherical shell

I=(2/3)mr2

since V=rW

=>mgh =(1/2)mV2 + (1/2)(2/5)mr2(V/r)2

gh =(1/2)V2 +(1/5)mV2

=>h=(7/10)(V2/2g)

h=(7/10)(9.62/9.81)

h=6.576 m

b)

By Conservation of energy

(1/2)mV2 =mgh

(1/2)*9.62 =9.81*h

h=4.7 m