HW 10 Begin Date: 4/6/2018 12:01:00 PM -- Due Date: 4/16/2018 11:59:00 PM End Da
ID: 2041155 • Letter: H
Question
HW 10 Begin Date: 4/6/2018 12:01:00 PM -- Due Date: 4/16/2018 11:59:00 PM End Date: 4/16/2018 11:59:00 PM (9 %) Problem 10: A man of mass m 74 kg and total volume V o floats in freshwater. When his lungs are empty, the volume of his body above the water is /jVo, and when his lungs are full his volume above the water is /iVo- >?50% Part (a) What is the volume of air that he can inhale (his lung capacity) in terms of 1-2. his mass and the density of water ? Ncglcct thc wcight of air in his lungs Grade Summary Deductions Potential 0% 100% 78 9MF 456- Submissions Attempts remaining: 4 detailed view (O% per attempt) 0% 0% 0% 0% "VO BACKSPACE | DELI CLEAR ? Submit Hint give up! Hints: 090 deduction per hint. Hints remaining: 2 Feedback: 0%-deduction per feedback. 50% Part (b) Calculate the volume of air, in liters, that he inhales, if 1 0.0275 and 2 0.0525. Use 1000 kg/m3 for the density of waterExplanation / Answer
a)
Volume of air that he can inhale is
Vair = f2Vo -f1Vo =(f2-f1)Vo
Vair =(f2-f1)m/p
(Since Vo=m/p)
b)
Vair =(0.0525-0.0275)(74/1000)
Vair =0.00185 m3
1 m3=1000 L
Vair =0.00185 *1000 =1.85 Litres
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