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Question 14, chap 6, sect 6 part 1 of 1 10 points A block of mass m slides on a

ID: 2039228 • Letter: Q

Question

Question 14, chap 6, sect 6 part 1 of 1 10 points A block of mass m slides on a horizontal frictionless table with an initial speed v. It then compresses a spring of force constant k and is brought to rest. The acceleration of gravity is 9.8 m/s How much is the spring compressed z from its natural length? 2 g 1m 3. mg 7n 6. x = Tm mg Tn m k 10.vo m g TTL Question 15, chap 6, sect 4. part 1 of 1 10 points Mary weighs 495 N and she walks down a flight of stairs to a level 4.1 m below her starting point. What is the change in Mary's potential en- ergy? Answer in units of J.

Explanation / Answer

given block of mass m

initial speed = vo

spring constant = k

acceleration due to gravity, g = 9.8 m/s

the block comes to rest on compresing the spring

a. compression of spring = x

form ocnservation of energy

0.5mvo^2 = 0.5kx^2

x = vo*sqrt(m/k)

hecne option 2. is the correct answer

b. Weight mg = 495 N

h = 4.1 m

hence chang ein PE = mgh = 495*4.1 = 2029.5 J

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