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Example. An object of mass 10.0 kg moving at the speed of v,broke into two parts

ID: 2039101 • Letter: E

Question

Example. An object of mass 10.0 kg moving at the speed of v,broke into two parts. Mass of the first new part equals to p-part of the mass of the initial object Speeds of the first and the second new parts are V1 and Vah respectively. Please, describe the disintegration: elastic, partly inelastic, or perfectly inelastic? Find the loss of kinetic energy AKE and the unknown magnitudes in the table. Results should be submitted in up to three significant figures. AKE Description of disintegration if 28 90.0 1.35.103 20.0

Explanation / Answer

Here, it is given that one object breaks into two subobjects

Given,

Mass of object (m) = 10kg

The velocity of an object (Vi) = 1.35*10^3 cm/s or 13.5 m/s

After spliting object have two parts

Part 1- mass (m1) is equal to 90% of m = 0.90*10kg = 9kg

Velocity (V1f) of mass (m1) is 20 m/s

Part 2- mass (m2) is equal to 1 kg (m-m1)

Velocity (V2f) of part 2 is we have to find

Applying momentum conservation principle

m*Vi = (m1*V1f + m2* V2f)

10*13.5 = 9*20 + 1* V2f

V2f= -45 m/s ( - sign showing opposite direction)

Now, loss of Kinetic energy

Before spliting K.E is

K.E(i) = 1/2*m*Vi^2

K.E (i) = 0.5* 10* 13.5^2

K.E(i) = 911.25 J

Now after splitting

K.E (part 1) = 0.5 * 9 * 20^2 = 1800 J

K.E (part 2) = 0.5 * 1 * 45^2 = 1012.5 J (Opposite direction)

Total K.E (t)= 1800-1012.5 = 787.5 J

Now, total K.E loss

K.E (loss) = K.E (i) - K.E (t)

K.E (loss) = 911.25 - 787.50 = 123.75 J

Lastly, here the typle of disintegration is Pure elastic because after spliting into two part the velocities are unequal which is only happen in elastic.

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