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e File Edit View History Bookmarks People Window Help C Home | Chegg.com nA Coll 11 Ch 18 HW S16 x o O www.webassign.net/web/Student/Assignment-Responses/last?dep- 18192730 8. -/1 points SerCP7 18.P.002.soln. A 5.0 ? resistor, an 8.0 ? resistor, and a 9 ? resistor (a) What is the equivalent resistance? are connected in series with a 23 V battery. (b) What are the currents in each resistor? A (5.0 ? resistor) A (8.0 2 resistor) A (9 resistor) (c) Repeat for the case in which all three resistors are connected in parallel across the battery. ? (equivalent resistance) A (5.0 ? resistor) A (8.0 2 resistor) A (9 2 resistor) 9. -11 points SerCP7 18.P.008. (a) Find the equivalent resistance of the circuit in Figure P18.8. (RI 5.00, R2-: 14.0 ?) (b) If the total power supplied to the circuit is 3.00 W, find the emf of the battery F6 97 F& FA F5 FI

Explanation / Answer

given R1 = 5 ohms , R2 = 8 ohms and R3 = 9 ohms

v = 23 v

A) equivalent resistance R = R1 + R2 + R3

= 5 + 8 + 9

= 22 ohms

b) current in the circuit i = V / R  

= 23/22

= 1.045 A

The same current flow through the all resistors connected in series

hence current through 5 ohms = 1.045 A

current through 8 ohms = 1.045 A

current through 9 ohms = 1.045 A

c) now equivalant resistance R = (R1R2 + R2R3 + R3R1) / ( R1+R2+R3)

= ( 40 + 72 + 45 ) / (5+8+9)

= 7.14 ohms

current through 5 ohms = V/R1 = 23 / 5 = 4.6 A

current through 8 ohms = V/R2 = 23/8 = 2.9 A

current through 9 ohms = V/R3 = 23/9 = 2.5 A

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