Two blocks are free to slide along the frictionless wooden track shown below. Th

Question

Two blocks are free to slide along the frictionless wooden track shown below. The block of mass m-1 5.05 kg is released from the position shown, at height h - 5,00m above the flat part of the track. Protruding from its front end is the north pole of a strong magnet, which repels the north pole of an identical magnet embedded in the back end of the block of mass m2 9.30 kg, initially at rest. The two blocks never touch. Calculate the maximum height to which m1 rises after the elastic collision. Need Help?etoi

Explanation / Answer

By Conservation of energy

(1/2)m1V12= m1gh

(1/2)*V12 =9.81*5

V1=9.9 m/s

Speed of block V1 after collision

V1f =(m1-m2)/(m1+m2)V1 =(5.05-9.3)*9.9/(5.05+9.3)

V1f=-2.933 m/s

After collision by conservation of energy

(1/2)m1V1f2 =m1gH

(1/2)*(-2.933)2 =9.81*H

H=0.4385 m

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