1. Two particles, each with a mass of 0.44kg collide. One particle was stationar
ID: 2038835 • Letter: 1
Question
1. Two particles, each with a mass of 0.44kg collide. One particle was stationary. (Refer to the above diagrams for mi and m2 notation.) After a perfectly elastic collision the moving particle has a speed of 0.5 m/s at an angle of 40° above the x axis or v-0.5 m/s ?40° What is (a) the magnitude of the moving particle's momentum, (b) its x-component of momentum and (c) its y-component of momentum? Hint:-mv,-=nn. /-m 2. The stationary particle involved in the collision of Problem #1 has a speed of 0.418 m/s at angle of-50° orv 0.418 m/s -50° after the collision, what is (a) the magnitude of the stationary particle's momentum, (b) its x-component of momentum and (c) its y-component of momentum? ( if you compare the y-components for problem #1 and #2 they should be equal and opposite. This will not be the case in the experiment because the collision is not perfectly elastic.)Explanation / Answer
1)
Mass m1 = m2 = m = 0.44 kg
v =
velocity after collision = 0.5 m/s
Angle = 40 degree
Now
x-component of momentum of moving particle = mvx = 0.44*0.5*cos40 = 0.1685 kg*m/s
y-component of momentum of moving particle = mvy = 0.44*0.5*sin40 = 0.1414 kg*m/s
Total momentum = 0.22 kg*m/s
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.