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& LON-CAPA Review: Volte x \\ e Three Equal Resistors i C \\ C Chegg Study | Gui

ID: 2038748 • Letter: #

Question

& LON-CAPA Review: Volte x e Three Equal Resistors i C C Chegg Study | Guided S × G decending orer-Google ? ? C Secure https://capa8.phy.ohio.edu/resohiou/physic slib/problems/59 CircuitsDC VoltageDividerFSROI problem?symbzuploaded%2fohiou%2f4A391 81ac4e295a52 ? Mail D student center-Blackboard LON-CAPA Launchpad QQuizlet ? WordPress.com 0 Chase Banking a Amazon O YouTube There are a variety of sensors which work on the basis of changing resistance due to an external influence. For example, force-sensitive resistors FSR will change their resistance when a force is a exerted when you fault-... Q ?| squeeze them) Computers are good at reading out voltages, so these devices are often combined ith a fixed-value resistor to create a voltage divider circuit. Consider the circuit shown below where the fixed resistor, R, has a resistance of 19.0 k? and the FSR has a resistance of 60.0 k? when there is no force acting on the FSR. A voltage V-5.00 V is being applied to the two series resistors. FSR What is the current flowing through the FSR when there is no force being applied to the FSR? Submit Answer Tries 0/10 What is the current flowing through the fixed resistor when there is no force being applied to the FSR? Submit Answer Tries 0/10 Consider the negative terminal of the voltage source to be at a potential of zero Volts. What is the electric potential (voltage) at the location A between the two resistors? Submit Answer Tries 0/10 Suppose that if a force of 1.30 N is applied to the FSR, its resistance decreases to 4.00 k2. What would be the new current through the fixed resistor, R? Submit Answer Tries 0/10 What would be the electric potential at Location A between the two resistors with the applied force of 1.30 N? 12:22 PM O Type here to search /10/2018

Explanation / Answer

a)

equivalent resistance

Req =19+60 =79 Kohms

IFSR =V/R =5/79000

IFSR=6.33*10-5 A

b)

IFixed =6.33*10-5 A

c)

VA=(6.33*10-5)(19000)=1.203 Volts

d)

Req=19+4 =23 Kohms

I=5/23000 =2.174*10-4 A

e)

VA=(2.174*10-4)(19000)=4.13 Volts