5. 0/1 points I Previous Answers SerPSE10 2.1.0P002.M My Notes A person walks fi

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5. 0/1 points I Previous Answers SerPSE10 2.1.0P002.M My Notes A person walks first at a constant speed of 5.30 m/s along a straight line from point to point and then back along the line from at a constant speed of 2.70 m/s. (a) What is her average speed over the entire trip? Use the symbol d to represent the distance between points A and B. The average speed is defined as the total distance traveled divided by the total time interval. m/s (b) What is her average velocity over the entire trip? The average velocity is defined as the displacement divided by the time. What is the displacement for the entire trip? m/s Need Help? Read ItMaster it Master It Submnt Answer Save Progress Pradice Anoher Version Practice Another Version

Explanation / Answer

(a) Average speed = Total distance travelled / total time interval

As ,Total diatance travelled is unknown , so let distance travelled be 'd' and total ditance travelled is '2d' (as distance is same from A to B and back from B to A )

therefore by using speed = distance / time

or, time= distance / speed

time taken to travel from A to B is,

= d/5.30 s......(i)

time taken to travel back from B to A,

= d/2.70 s ......(ii)

total time intervals is (i) + (ii)

= d/5.30 + d/2.70 = (2.70d +3.50d)/(5.30 * 2.70) = 8d/14.31

Therefore, Average speed = 2d/(8d/14.31) = (2d*14.31)/8d

=3.57 m/s

(b) Average velocity = displacement / time

As the person is comingback to the point A from where she has started the total displacement is Zero

Therefore, Average velocity = 0 m/s

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