16 23.2.WA 014 My Notes Ask Your A solenold with 1200 turns per meter has a diam

Question

16 23.2.WA 014 My Notes Ask Your A solenold with 1200 turns per meter has a diameter of 8.00 cm. A current 1 2.48 A flows in the counterclockwise solenoid. A rectangular loop of length L 16.0 cm, width w 12.5 cm, and 2 turns is centered on the axis of the solenoid (a) Find the magnitude of the magnetic flux through the loop 1.B8E-6 (b) When the current is increased to 5.55 A, the magnit take for the current to get to this value? ude of the induced emf in the rectangular loop is 116 mV. How long did it is the magnitude of the change in flux? How is the induced emf related to the change in flux? ms

Explanation / Answer

a) B = mu0 N I = 4 pi * 10-7 * 1200 * 2.48 = 3.74 * 10-3 T

phi = B A = 3.74 * 10-3 * pi * (0.042)

= 1.88 * 10-5 wb

b) phifinal = 2 B A = 2 * 4 pi * 10-7 * 1200 * 5.55 * pi * 0.042 = 8.4 * 10-5 wb

phiinitial = 2 B A = 2 * 4 pi * 10-7 * 1200 * 2.48 * pi * 0.042 = 3.75 * 10-5 wb

t = phifinal - phiinitial / t

= (8.4 * 10-5) - (3.75 * 10-5) / (116 * 10-3)

= 4 * 10-4 s = 0.400 ms

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