0-13 points SerPSET9 28.P.039 A 2.00-nF capacitor with an initial charge of 4.58

Question

0-13 points SerPSET9 28.P.039 A 2.00-nF capacitor with an initial charge of 4.58 HC is discharged through a 1.55-kf2 resistor. (a) Calculate the current in the resistor 9.00 ?s after the resistor is connected across the terminals of the capacitor. (Let current be define such that > 0.) dQ , o dt mA (b) What charge remains on the capacitor after 8.00 us? HC (c) What is the (magnitude of the) maximum current in the resistor? Need Help? ReaWatch Watch It -/1 points SerPSET928.P 040. A 13.0 uF capacitor is charged by a 9.0 V battery through a resistance R. The capacitor reaches a potential difference of 4.00 v begins. Find R. Need Help? Read It Submit Answer Save Progress Practice Another Version

Explanation / Answer

part a )

time constant = t = RC

t = 2 x 10^-9 F * 1.55 x 10^3 = 3.1 x 10^-6 s

The discharge current in the circuit as a function of time is given by  

i = (qo/RC) * e^-T/t

T = given time = 9 x 10^-6 s

qo = initial charge = 4.58 x 10^-6 C

i = (4.58 *10^-6 / 3.1 *10^-6) * e^-(9x10^-6/3.1x10^-6)

i = 0.08 A = 80 mA

part b )

The charge on the capacitor discharging through a resistance as a function of time is given by

q = qo*e^-T/t

q = 0.3468 x 10^-6 C = 0.35 uC

part c )

Imax = qo/RC = 1.48 A

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