solve these using trig please. I solved a already and a = 13.04 miles When the s

Question

solve these using trig please.
I solved a already and a = 13.04 miles

When the sun is directly overhead, the sun's light is filtered by approximately 10 miles of atmosphere. As the sun sets, the intensity decreases because the light must shown below. Note: 3947 mi is the radius of Earth. 2. pass a greater distance through the atmosphere, as sun at noon Atmosphere 500 G10 mi 3947 mi Find the distance d in the figure when the angle of elevation of the sun is 50° a. b. If the sun is directly overhead at 12 noon, then at what time is the angle of elevation of the sun 50°? The distance from the earth to the sun is 93 million miles. Give your answer in hours and minutes, i.e. 3:35. Find the distance that the sunlight passes through the atmosphere at sunset (angle of elevation 0%).

Explanation / Answer

a )

L = 3947 + 10 = 3957 mi

angle is 90 + 50 = 140

now using sine rule

3957 / sin140 = 3947 / sin C

C = sin-10.6411

C = 39.87o

angle A = 180 - ( 140 + 39.87 )

A = 0.13o

d / sin0.13 = 3957 / sin140

d = 13.96 miles

b )

90 - 50 = 40o

40 X 1/0.004166

= 9601.536 sec

c )

the length is

= ( 39572 - 39472 )1/2

= 281.14 miles

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.