solve step 3 and step 4 please and thank you! Begin \"molecular\" equation. A. K

Question

solve step 3 and step 4 please and thank you!

Begin "molecular" equation. A. K_2CO_3(aq) + Ca(NO_3)_2(aq) rightarrow Step #2. Continue the "molecular" equation (A.) by writing the correct formula for each product formed remembering that the ratio of (+) and (-) ions must be such that the compound is charge neutral overall. A. K_2CO_3(aq) + Ca(NO_3)_2(aq) rightarrow CaCO_3 + KNO_3 Step #3. Balance the "molecular" equation. Remember that the equation will never balance if formulas for reactants and product are not written correctly. A. K_2CO_3(aq) + Ca(NO_3)_2(aq) rightarrow CaCO_3 + 2 KNO_3 Step #4 Use solubility rules to predict states of products. Note that all reactants are aqueous. A. K_2CO_3(aq) + Ca(NO_3)_2(aq) rightarrow CaCO_3 (s) + 2 KNO_3 (aq)

Explanation / Answer

The reaction is already balanced; I believe you are trying to figure out how we arrived at the reactions and balanced the same. I will try to explain how we arrived at the balanced equation. First we note the charges on the ions involved:

Ion

Charge

K

+1

CO3

-2

Ca

+2

NO3

-1

Note that carbonate and nitrate are radicals while K and Ca are elements. Now we answer question (2).

This reaction is a double displacement reaction, where the counter-ions change position. Thus the combination of our reactants will yield

K2CO3 (aq) + Ca(NO3)2 (aq) ---------> CaCO3 + KNO3

Both the anions (negatively charged ions) have changed their positions. Next we answer part (3).

We need to balance charges on the ions in such a way that the compound resulting from the combination of the positive and negative ions is electrically neutral.

CO3 ion has -2 charge while Ca ion has +2 charge. The neutralized compound will be CaCO3 (+2 and -2 charges balance each other). Similarly, K ion has +1 positive charge while NO3 ion has -1 negative charge. The resulting compound from the combination of these two ions is KNO3. Also, note that we have 2 K+ ions on the reactant side while we have only 1 on the product side. Hence we multiple KNO3 on the product side by 2 to balance the number of K+ ions. This also balances the number of NO3- ions on both sides. Thus, the balanced equation is

K2CO3 (aq) + Ca(NO3)2 (aq) --------> CaCO3 + 2 KNO3

Next we answer part (4). Both the reactants are aqueous, i.e, they are soluble in water. All sodium and potassium salts are water-soluble, hence KNO3 is present in aqueous condition. However, CaCO3 is not soluble in cold water and sparingly soluble in hot water. Thus it will separate out as solid. Thus we have the fully balanced equation (indicating states of the compounds) as

K2CO3 (aq) + Ca(NO3)2 (aq) -----------> CaCO3 (s) + 2 KNO3 (aq)

Ion

Charge

K

+1

CO3

-2

Ca

+2

NO3

-1

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