13. A 10.0–kg block is released from rest at point A in the figure below. The tr

Question

13. A 10.0–kg block is released from rest at point A in the figure below. The track is frictionless except for the portion between points B and C, which has a length of 6.00 m. The block travels down the track, hits a spring of force constant 2 151 N/m, and compresses the spring 0.310 m from its equilibrium position before coming to rest momentarily. Determine the coefficient of kinetic friction between the block and the rough surface between points B and C. Formula used and step by step please thank you

Explanation / Answer

initial energy Ei = mgh
final energy Ef = ½kx²
work done by friction W = ?mgdcos(180) = -?mgd
W = Ef - Ei
-?mgd = ½kx² - mgh
so
? = h/d - kx²/(2mgd)
= 3.00/6.00 - 2151*0.310²/(2*10.0*9.81*6.00)
= 0.324

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.