rigid landing 3500 3000 2500 2000 1000 00 02 04 06 08 1012 14 time (s) soft land
ID: 2036804 • Letter: R
Question
rigid landing 3500 3000 2500 2000 1000 00 02 04 06 08 1012 14 time (s) soft landing 2 1500 a5 1.0 1.5 2.0 0.0 time (a) 3. Considering the rigid and soft drop landings and keeping in mind that the drop distance was the same for these two landing conditions (50 cm) a How would the participant's downward veloaity at the instant of ground contact fie, right at the instant the partiojpant first toucthed the ground) compare for the two landing techniques given drop helight was same (50 cm) for both? Explain. (4 pts) b How would the magnitude of the impuise required to stop the downward motion of the body compare for the two landing techniques? Explain. [Hint think about your response to 3a and the change in momentum that must be accomplished] (6 pts) c. Explain the difterences between the vertical ground reaction farce profisies for the two landing techniques using the impulbe-momentum principle (F-m v) (6 pts)Explanation / Answer
a) participant downwards velocity only depends on the height from which it drops and not on the nature of surface it strikes. Therefore the velocity in both cases is same.
b) impulse is defined as the change in momentum of the body. To stop the participant magnitude of impulse required is equal to the initial momentum of the participant which is again same in both the cases therefore impulse required to stop the participant is same for both the cases.
c) impulse is also defined as the product of average impulsive force and the time of impact. Now, in the case of soft landing the time interval is greater than that in the case of rigid landing therefore to keep the product a constant the force is greater in the case of rigid landing. Also, to understand logically a rigid surface will provide greater force off course.
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