Both questions needed. 3. 25/10 points | Previous Answers SerPSE9 15.P027.WI. My

Question

Both questions needed. 3. 25/10 points | Previous Answers SerPSE9 15.P027.WI. My Notes Ask Your Teach A 60.0-g object connected to a spring with a force constant of 40.0 N/m oscillates with an amplitude of 6.00 cm on a frictionless, horizontal surface. (a) Find the total energy of the system. 72 (b) Find the speed of the object when its position is 1.10 cm. (Let 0 cm be the position of equilibrium.) m/s (c) Find the kinetic energy when its position is 3.50 cm. mJ (d) Find the potential energy when its position is 3.50 cm. mj Need Help?adWatch N

Explanation / Answer

Solution :-

Part A)

E = .5kA2

E = (.5)(40)(.06)2

E = .072 J

That is 72 mJ

Part B)

.072 = .5kx2 + .5mv2

.072 = (.5)(40)(.011)2 + (.5)(.060)(v2)

v = 1.523 m/s

Part C)

.072= .5kx2 + KE

.072 = (.5)(40)(.035)2 + KE

KE = .0475 J

That is 47.5 mJ

Part D)

72 - 47.5 = 24.5 mj

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