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A small rock passes a massive star, following the path shown in red on the diagr

ID: 2036518 • Letter: A

Question

A small rock passes a massive star, following the path shown in red on the diagram above. When the rock is a distance 3.1e+13 m (indicated as d1 on the diagram) from the center of the star, the magnitude of its momentum p1 is 1.2e+17 kg · m/s, and the angle ? is 114 degrees. At a later time, when the rock is a distance d2 = 7.13e+12 m from the center of the star, it is heading in the -y direction. There are no other massive objects nearby.

What is the magnitude of the momentum p2? (kg · m/s)

Pi d2 Star P2 A small rock passes a massive star, following the path shown in red on the diagram above. When the rock is a distance 3.1e+13 m (indicated as d1 on the diagram) from the center of the star, the magnitude of its momentum p1 is 1.2e+17 kg-m s, and the angle ? is 11 degrees. At a ater time when he rock sa distance d 7, Lel m from the center of the star, it is heading in the -y direction. There are no other massive objects nearby. What is the magnitude of the momentum p2 kg m/s

Explanation / Answer

Using the law of conservation of angular momentum.

Angular momentum, L = R*P*sin(theta)

P = Linear momentum

R = distance from the axis of rotation

As per law of conservation of angular momentum,

=>Total initial angular momentum = Total final angular momentum

=>(3.1*10^13)*(1.2*10^17)*sin(114) = (7.13*10^12)*(P2)*sin(90)

=>(3.1*10^13)*(1.2*10^17)*(0.9135) = (7.13*10^12)*P2*1

=>(3.398*10^30) = (7.13*10^12)*P2

=> P2 = (3.398*10^30)/(7.13*10^12)

=> P2 = 4.76577*10^17

Final momentum, P2 = 4.77*10^17 kg m/s

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