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ID: 2036101 • Letter: A

Question

a Secure I https://session.masteringphysics.com/myct/itemView?assignmentProblemID-93941640 Chapter 30 Homework Problem 30.51 4 of 17 udy M erials Constants I Periodic Table Part A A 15 kS2 resistor in series with a 330 mH inductor is driven by an ac power supply. At what frequency is the impedance double that of the impedance at 40 Hz? Express your answer using two significant figures. f 08 SubmitP X Incorrect, One attempt remaining; Try Again kHz Previous Answers Request Answer Provide Feedback Next

Explanation / Answer

Here , for the impedance at the frequency f

Z = sqrt(R^2 + (2pi * f* L)^2)

Now, let the second frequency is f

for the impedance to be double

sqrt(1500^2 + (2pi * 40 * 0.330)^2) * 2 = sqrt(1500^2 + (2pi * f * 0.330)^2)

solving for f

f = 1255 Hz

the frequency is 1255 Hz

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