Print Your Name and TUID: Section: Instructions: Solve the problem below using t

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Print Your Name and TUID: Section: Instructions: Solve the problem below using the RIDEA framework A complete solution worth 27 pts Problem 2 In the circuit shown, let C.-2.00uF, ?-300, F, C-4.00aF and Va-24.0V. Find the energy stored GtheC2 C3 C2-capacitor. ab-24.0V. Find the energy stored (in ul) in the 1) Represent the problem in terms of symbols and diagrams 2) Interpret the problem by identifying applicable concepts and principles 3) Develop a plan for solving the problem 4) Evaluate your answer 5) Assess your answer

Explanation / Answer

Remember:
For parallel combination
Ceq = C1 + C2 + C3 +...............
for series combination
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ............
for 2 capacitors in series it will be
Ceq = C1*C2/(C1+C2)
Using this Information:

C2 and C3 are in Series, So

C23 = C2*C3/(C2 + C3) = 3*4/(3 + 4) = 1.71 uF

Now C23 and C1 are in parallel, So

Ceq = C23 + C1 = 1.71 + 2.00 = 3.71 uF

Now we know that

Qeq = Ceq*V

Qeq = 3.71*24 = 89.04 uC

Now remember in capacitors parallel combination voltage distribution in each part will be same and in series combination charge distribution in each capacitor will be same.

Voltage on C23 = Voltage on C1 = V = 24 V

Charge on C23 = Q23 = C23*V23

Q23 = 1.71*24 = 41.04 uC

Since C3 and C2 are in series, So

Charge on C2 = Charge on C3 = 41.04 uC

Q2 = 41.04 uC

Energy stored in C2 will be

U2 = Q2^2/(2*C2)

U2 = (41.04*10^-6)^2/(2*3*10^-6)

U2 = 280.71*10^-6 J

U2 = 280.71 uJ

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