An electron moves in the magneic teld0 460 i T with a speed of 0 700 x10 a/s in

Question

An electron moves in the magneic teld0 460 i T with a speed of 0 700 x10 a/s in the drecions shown in the tqure For each what is magnetic force Fon the electron? (Figue ) You may want to neviewPoe15 820 For help with math skils you may want to review Part A Express vector Fin the form of F. F?. F, , where the View Available Hinns) and components are separated by commas. Part B Express vector F in the form of F..F, F. where the x y and z components are separated by commas View Avaslable Hs Submi Provide Feedback Figure

Explanation / Answer

part(A)

velocity v = -0.7*10^7 j m/s

magnetic field B = 0.46 i

charge q = -1.6*10^-19 C

magnetic force Fb = q*( v X B ) = q*( cross product of v and B )

Fb = -1.6*10^-19*(-0.7*10^7 j X 0.46 i)

Fb = -5.152*10^-13 N k

F = 0 i + 0j - 5.152*10^-13 k N

F = 0 , 0   , -5.152*10^-13 N
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part B

velocity v = -0.7*10^7*cos45 j + 0.7*10^7*sin45 k m/s

magnetic field B = 0.46 i

charge q = -1.6*10^-19 C

magnetic force Fb = q*( v X B ) = q*( cross product of v and B )

Fb = -1.6*10^-19*((-0.7*10^7*cos45 j + 0.7*10^7*sin45 k) X 0.46 i)

Fb = -3.64*10^-13 N k - 3.64*10^-13 j N

F = 0 i - 3.64*10^-13 j N -3.64*10^-13 N k

F = 0 , -3.64*10^-13 N , -3.64*10^-13 N

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