:) Class Management Help HW 8 Begin Date: 3/23/2018 12:05:00 AM - Due Date: 4/2/

Question

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Class Management Help HW 8 Begin Date: 3/23/2018 12:05:00 AM - Due Date: 4/2/2018 12:05:00 AM End Date: 5/4/2018 1:00:00 AM (10%) Problem 10: After a party the host pours the remnants of several bottles of wine into a Jug. He then inserts a cork with a 1.95-cm diameter into the jug, placing it in direct contact with the wine. He is amazed when he pounds the cork into place that the bottom of the jug, with a 11.5-cm diameter, breaks away Randomized Variables di-1.95 cm d2 11.5 cm F- 130 N ? Find the force the host causes to be exerted on the bottom by pounding the cork with a 130-N force. Ignore the force caused by the weight of the wine Grade Summary Deductions Potential bottom 0% 100% sin cotan asin acos0 atan acotan0sinh coshtanhcotanh tan() | ? Submissions Attempts remaining: 5 co *1 2 3 % per attempt) detailed view END Degrees Radians VO CLEAR Submit Hint I give up! Hints : 090 deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback.

Explanation / Answer

The "extra" force is

F = 130N * (11.5cm / 1.95cm)² = 4521.37 N

This is because the "extra" pressure is the same everywhere in the jug, and the extra force is proportional to the area, which is proportional to the square of the diameter.

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